[TAG] Ya know, I've changed my mind.

[Jimmy O'Regan]

Karl-Heinz Herrmann wrote:
> On Mon, 07 Nov 2005 00:07:23 +0000
> "Jimmy O'Regan" <jimregan at o2.ie> wrote:
> 
> 
>>$15.4 = \sqrt{height^{2} + (height \times (16 \div 9))^{2}}$
> 
> 
> Well -- this would look a little more like it should:
> 
> $15.4 = \sqrt{height^{2} + (height \cdot (\frac{16}{9}))^{2} }$
> 
> \frac{top}{bottom} puts an actual fraction, and I would even drop the
> \cdot as at that point its clrearly a multiplication (for me) if nothing
> is there. 
> 
> But I wouldn't call that TeX code cryptic and you allways can run it
> through [La]TeX to get a better impression :-)
> 
> K.-H.

Ah. It's been more than a year since I even looked at TeX, and I've 
never made any "real" use of it--just bits and pieces at Wikipedia and PGDP.